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100n^2+9=58
We move all terms to the left:
100n^2+9-(58)=0
We add all the numbers together, and all the variables
100n^2-49=0
a = 100; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·100·(-49)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{19600}=140$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-140}{2*100}=\frac{-140}{200} =-7/10 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+140}{2*100}=\frac{140}{200} =7/10 $
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